Search a number
-
+
531040015511344 = 2433190000969459
BaseRepresentation
bin111100010111110100110001…
…1011111000110111100110000
32120122020221002201221102110101
41320233221203133012330300
51024101024422432330334
65121232225410442144
7216566242426466413
oct17057514337067460
92518227081842411
10531040015511344
11144229895631749
124b687142893354
1319a40b21422321
14951c68c4d7b7a
15415d881e8b214
hex1e2fa637c6f30

531040015511344 has 10 divisors (see below), whose sum is σ = 1028890030053260. Its totient is φ = 265520007755664.

The previous prime is 531040015511339. The next prime is 531040015511371. The reversal of 531040015511344 is 443115510040135.

It is a super-2 number, since 2×5310400155113442 (a number of 30 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16595000484714 + ... + 16595000484745.

It is an arithmetic number, because the mean of its divisors is an integer number (102889003005326).

Almost surely, 2531040015511344 is an apocalyptic number.

It is an amenable number.

531040015511344 is a deficient number, since it is larger than the sum of its proper divisors (497850014541916).

531040015511344 is a wasteful number, since it uses less digits than its factorization.

531040015511344 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33190000969467 (or 33190000969461 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 531040015511344 its reverse (443115510040135), we get a palindrome (974155525551479).

The spelling of 531040015511344 in words is "five hundred thirty-one trillion, forty billion, fifteen million, five hundred eleven thousand, three hundred forty-four".

Divisors: 1 2 4 8 16 33190000969459 66380001938918 132760003877836 265520007755672 531040015511344