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53104121 = 77586303
BaseRepresentation
bin1100101010010…
…0110111111001
310200220222011022
43022210313321
5102043312441
65134112225
71213243340
oct312446771
9120828138
1053104121
1127a80a04
121594b675
13b004275
1470a4b57
1549de84b
hex32a4df9

53104121 has 4 divisors (see below), whose sum is σ = 60690432. Its totient is φ = 45517812.

The previous prime is 53104091. The next prime is 53104169. The reversal of 53104121 is 12140135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53104121 - 26 = 53104057 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53104121.

It is not an unprimeable number, because it can be changed into a prime (53104721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3793145 + ... + 3793158.

It is an arithmetic number, because the mean of its divisors is an integer number (15172608).

Almost surely, 253104121 is an apocalyptic number.

It is an amenable number.

53104121 is a deficient number, since it is larger than the sum of its proper divisors (7586311).

53104121 is an equidigital number, since it uses as much as digits as its factorization.

53104121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7586310.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 53104121 is about 7287.2574402171. The cubic root of 53104121 is about 375.8743945361.

Adding to 53104121 its reverse (12140135), we get a palindrome (65244256).

The spelling of 53104121 in words is "fifty-three million, one hundred four thousand, one hundred twenty-one".

Divisors: 1 7 7586303 53104121