Base | Representation |
---|---|
bin | 1111011101001010001… |
… | …00001101000011110101 |
3 | 1212202201210212101221201 |
4 | 13232211010031003311 |
5 | 32200042340220432 |
6 | 1043543335212501 |
7 | 53236631146102 |
oct | 7564504150365 |
9 | 1782653771851 |
10 | 531050320117 |
11 | 195243074589 |
12 | 86b07817131 |
13 | 3b101cbb065 |
14 | 1b9bad57aa9 |
15 | dc31a7cee7 |
hex | 7ba510d0f5 |
531050320117 has 2 divisors, whose sum is σ = 531050320118. Its totient is φ = 531050320116.
The previous prime is 531050320111. The next prime is 531050320139. The reversal of 531050320117 is 711023050135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 407198410641 + 123851909476 = 638121^2 + 351926^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-531050320117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531050320111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265525160058 + 265525160059.
It is an arithmetic number, because the mean of its divisors is an integer number (265525160059).
Almost surely, 2531050320117 is an apocalyptic number.
It is an amenable number.
531050320117 is a deficient number, since it is larger than the sum of its proper divisors (1).
531050320117 is an equidigital number, since it uses as much as digits as its factorization.
531050320117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3150, while the sum is 28.
The spelling of 531050320117 in words is "five hundred thirty-one billion, fifty million, three hundred twenty thousand, one hundred seventeen".
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