Base | Representation |
---|---|
bin | 11000001001100100110011… |
… | …01001101110110011110111 |
3 | 20222000211201022221222121212 |
4 | 30010302121221232303313 |
5 | 23430040133144021211 |
6 | 304540204322432035 |
7 | 14120515056555044 |
oct | 1404623151566367 |
9 | 228024638858555 |
10 | 53105553501431 |
11 | 15a14a36546772 |
12 | 5b5826650261b |
13 | 2382aa8489322 |
14 | d18472d441cb |
15 | 6215e5e2a38b |
hex | 304c99a6ecf7 |
53105553501431 has 2 divisors, whose sum is σ = 53105553501432. Its totient is φ = 53105553501430.
The previous prime is 53105553501401. The next prime is 53105553501439. The reversal of 53105553501431 is 13410535550135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53105553501431 is a prime.
It is a super-2 number, since 2×531055535014312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53105553501439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26552776750715 + 26552776750716.
It is an arithmetic number, because the mean of its divisors is an integer number (26552776750716).
Almost surely, 253105553501431 is an apocalyptic number.
53105553501431 is a deficient number, since it is larger than the sum of its proper divisors (1).
53105553501431 is an equidigital number, since it uses as much as digits as its factorization.
53105553501431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 337500, while the sum is 41.
The spelling of 53105553501431 in words is "fifty-three trillion, one hundred five billion, five hundred fifty-three million, five hundred one thousand, four hundred thirty-one".
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