Base | Representation |
---|---|
bin | 11000001001101011110001… |
… | …10110000000100110100111 |
3 | 20222001012101021222012210011 |
4 | 30010311320312000212213 |
5 | 23430120320244223312 |
6 | 304542024045111051 |
7 | 14121006625606564 |
oct | 1404657066004647 |
9 | 228035337865704 |
10 | 53109298039207 |
11 | 15a16588206393 |
12 | 5b58b30558487 |
13 | 23832541a5057 |
14 | d1870a39986b |
15 | 621764a3cda7 |
hex | 304d78d809a7 |
53109298039207 has 4 divisors (see below), whose sum is σ = 53781567634720. Its totient is φ = 52437028443696.
The previous prime is 53109298039159. The next prime is 53109298039223. The reversal of 53109298039207 is 70293089290135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53109298039207 - 215 = 53109298006439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53109298039807) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 336134797638 + ... + 336134797795.
It is an arithmetic number, because the mean of its divisors is an integer number (13445391908680).
Almost surely, 253109298039207 is an apocalyptic number.
53109298039207 is a deficient number, since it is larger than the sum of its proper divisors (672269595513).
53109298039207 is an equidigital number, since it uses as much as digits as its factorization.
53109298039207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 672269595512.
The product of its (nonzero) digits is 7348320, while the sum is 58.
The spelling of 53109298039207 in words is "fifty-three trillion, one hundred nine billion, two hundred ninety-eight million, thirty-nine thousand, two hundred seven".
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