Base | Representation |
---|---|
bin | 110001011101100110… |
… | …111110000000110001 |
3 | 12002002100000211102002 |
4 | 301131212332000301 |
5 | 1332232141312423 |
6 | 40222021503345 |
7 | 3560055302453 |
oct | 613546760061 |
9 | 162070024362 |
10 | 53110104113 |
11 | 205842a6330 |
12 | a362571b55 |
13 | 50151c4b11 |
14 | 27db7d82d3 |
15 | 15ac937228 |
hex | c5d9be031 |
53110104113 has 16 divisors (see below), whose sum is σ = 59606269632. Its totient is φ = 46902048000.
The previous prime is 53110104101. The next prime is 53110104133. The reversal of 53110104113 is 31140101135.
53110104113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 53110104113 - 24 = 53110104097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53110104133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 147623 + ... + 357788.
It is an arithmetic number, because the mean of its divisors is an integer number (3725391852).
Almost surely, 253110104113 is an apocalyptic number.
It is an amenable number.
53110104113 is a deficient number, since it is larger than the sum of its proper divisors (6496165519).
53110104113 is a wasteful number, since it uses less digits than its factorization.
53110104113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 505696.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 53110104113 its reverse (31140101135), we get a palindrome (84250205248).
The spelling of 53110104113 in words is "fifty-three billion, one hundred ten million, one hundred four thousand, one hundred thirteen".
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