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53110104133 is a prime number
BaseRepresentation
bin110001011101100110…
…111110000001000101
312002002100000211102211
4301131212332001011
51332232141313013
640222021503421
73560055302512
oct613546760105
9162070024384
1053110104133
11205842a6349
12a362571b71
1350151c4b28
1427db7d8309
1515ac93723d
hexc5d9be045

53110104133 has 2 divisors, whose sum is σ = 53110104134. Its totient is φ = 53110104132.

The previous prime is 53110104101. The next prime is 53110104139. The reversal of 53110104133 is 33140101135.

53110104133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34489318369 + 18620785764 = 185713^2 + 136458^2 .

It is a cyclic number.

It is not a de Polignac number, because 53110104133 - 25 = 53110104101 is a prime.

It is a super-2 number, since 2×531101041332 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53110104139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26555052066 + 26555052067.

It is an arithmetic number, because the mean of its divisors is an integer number (26555052067).

Almost surely, 253110104133 is an apocalyptic number.

It is an amenable number.

53110104133 is a deficient number, since it is larger than the sum of its proper divisors (1).

53110104133 is an equidigital number, since it uses as much as digits as its factorization.

53110104133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 53110104133 its reverse (33140101135), we get a palindrome (86250205268).

The spelling of 53110104133 in words is "fifty-three billion, one hundred ten million, one hundred four thousand, one hundred thirty-three".