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5311040311 = 31171323881
BaseRepresentation
bin1001111001001000…
…00000101100110111
3111201010122210122201
410330210000230313
541334111242221
62235002005331
7245420045353
oct47444005467
914633583581
105311040311
112285a42215
1210427a6847
13668423905
1438550a463
152113e6891
hex13c900b37

5311040311 has 4 divisors (see below), whose sum is σ = 5482364224. Its totient is φ = 5139716400.

The previous prime is 5311040263. The next prime is 5311040323. The reversal of 5311040311 is 1130401135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5311040311 - 217 = 5310909239 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5311040351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85661910 + ... + 85661971.

It is an arithmetic number, because the mean of its divisors is an integer number (1370591056).

Almost surely, 25311040311 is an apocalyptic number.

5311040311 is a deficient number, since it is larger than the sum of its proper divisors (171323913).

5311040311 is a wasteful number, since it uses less digits than its factorization.

5311040311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171323912.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 5311040311 is about 72876.8846137100. The cubic root of 5311040311 is about 1744.7231861681.

Adding to 5311040311 its reverse (1130401135), we get a palindrome (6441441446).

The spelling of 5311040311 in words is "five billion, three hundred eleven million, forty thousand, three hundred eleven".

Divisors: 1 31 171323881 5311040311