Search a number
-
+
5311097323993 is a prime number
BaseRepresentation
bin100110101001001011000…
…0100011100000111011001
3200210201212111121121211001
41031102112010130013121
51144004111403331433
615143515011505001
71055466641245666
oct115222604340731
920721774547731
105311097323993
111768472a855aa
127193ab8b8161
132c6ab0034c76
141450b6690a6d
159324929657d
hex4d49611c1d9

5311097323993 has 2 divisors, whose sum is σ = 5311097323994. Its totient is φ = 5311097323992.

The previous prime is 5311097323991. The next prime is 5311097324089. The reversal of 5311097323993 is 3993237901135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5219886075849 + 91211248144 = 2284707^2 + 302012^2 .

It is a cyclic number.

It is not a de Polignac number, because 5311097323993 - 21 = 5311097323991 is a prime.

It is a super-2 number, since 2×53110973239932 (a number of 26 digits) contains 22 as substring.

Together with 5311097323991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (5311097323991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655548661996 + 2655548661997.

It is an arithmetic number, because the mean of its divisors is an integer number (2655548661997).

Almost surely, 25311097323993 is an apocalyptic number.

It is an amenable number.

5311097323993 is a deficient number, since it is larger than the sum of its proper divisors (1).

5311097323993 is an equidigital number, since it uses as much as digits as its factorization.

5311097323993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4133430, while the sum is 55.

The spelling of 5311097323993 in words is "five trillion, three hundred eleven billion, ninety-seven million, three hundred twenty-three thousand, nine hundred ninety-three".