Base | Representation |
---|---|
bin | 11000001001101111000000… |
… | …10001100111100110111111 |
3 | 20222001100212020020010101122 |
4 | 30010313200101213212333 |
5 | 23430132344013030421 |
6 | 304542512154301155 |
7 | 14121100626415001 |
oct | 1404674021474677 |
9 | 228040766203348 |
10 | 53111033330111 |
11 | 15a172987930a9 |
12 | 5b593357277bb |
13 | 238346c8598c3 |
14 | d18832a2a371 |
15 | 6218170632ab |
hex | 304de04679bf |
53111033330111 has 16 divisors (see below), whose sum is σ = 58050969320448. Its totient is φ = 48372943651200.
The previous prime is 53111033330107. The next prime is 53111033330161. The reversal of 53111033330111 is 11103333011135.
It is not a de Polignac number, because 53111033330111 - 22 = 53111033330107 is a prime.
It is a super-2 number, since 2×531110333301112 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53111033330161) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16533476 + ... + 19482758.
It is an arithmetic number, because the mean of its divisors is an integer number (3628185582528).
Almost surely, 253111033330111 is an apocalyptic number.
53111033330111 is a deficient number, since it is larger than the sum of its proper divisors (4939935990337).
53111033330111 is a wasteful number, since it uses less digits than its factorization.
53111033330111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2983502.
The product of its (nonzero) digits is 1215, while the sum is 26.
Adding to 53111033330111 its reverse (11103333011135), we get a palindrome (64214366341246).
The spelling of 53111033330111 in words is "fifty-three trillion, one hundred eleven billion, thirty-three million, three hundred thirty thousand, one hundred eleven".
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