Base | Representation |
---|---|
bin | 110001011101101011… |
… | …001100010010001101 |
3 | 12002002102010001222102 |
4 | 301131223030102031 |
5 | 1332232432224044 |
6 | 40222101324445 |
7 | 3560100563123 |
oct | 613553142215 |
9 | 162072101872 |
10 | 53111211149 |
11 | 20584992037 |
12 | a362a06725 |
13 | 50154c1979 |
14 | 27dba05913 |
15 | 15acaa524e |
hex | c5dacc48d |
53111211149 has 2 divisors, whose sum is σ = 53111211150. Its totient is φ = 53111211148.
The previous prime is 53111211089. The next prime is 53111211169. The reversal of 53111211149 is 94111211135.
53111211149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38026950025 + 15084261124 = 195005^2 + 122818^2 .
It is a cyclic number.
It is not a de Polignac number, because 53111211149 - 216 = 53111145613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53111211169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26555605574 + 26555605575.
It is an arithmetic number, because the mean of its divisors is an integer number (26555605575).
Almost surely, 253111211149 is an apocalyptic number.
It is an amenable number.
53111211149 is a deficient number, since it is larger than the sum of its proper divisors (1).
53111211149 is an equidigital number, since it uses as much as digits as its factorization.
53111211149 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1080, while the sum is 29.
The spelling of 53111211149 in words is "fifty-three billion, one hundred eleven million, two hundred eleven thousand, one hundred forty-nine".
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