Base | Representation |
---|---|
bin | 100110101001001100000… |
… | …0110001011100101100011 |
3 | 200210201221212121120011101 |
4 | 1031102120012023211203 |
5 | 1144004144110210021 |
6 | 15143522224455231 |
7 | 1055500533321325 |
oct | 115223006134543 |
9 | 20721855546141 |
10 | 5311131335011 |
11 | 17684901a5587 |
12 | 7193bb17a517 |
13 | 2c6ab70b2828 |
14 | 1450badc5615 |
15 | 9324c263a91 |
hex | 4d49818b963 |
5311131335011 has 2 divisors, whose sum is σ = 5311131335012. Its totient is φ = 5311131335010.
The previous prime is 5311131335009. The next prime is 5311131335023. The reversal of 5311131335011 is 1105331311135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5311131335011 - 21 = 5311131335009 is a prime.
It is a super-2 number, since 2×53111313350112 (a number of 26 digits) contains 22 as substring.
Together with 5311131335009, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5311131335051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655565667505 + 2655565667506.
It is an arithmetic number, because the mean of its divisors is an integer number (2655565667506).
Almost surely, 25311131335011 is an apocalyptic number.
5311131335011 is a deficient number, since it is larger than the sum of its proper divisors (1).
5311131335011 is an equidigital number, since it uses as much as digits as its factorization.
5311131335011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2025, while the sum is 28.
Adding to 5311131335011 its reverse (1105331311135), we get a palindrome (6416462646146).
The spelling of 5311131335011 in words is "five trillion, three hundred eleven billion, one hundred thirty-one million, three hundred thirty-five thousand, eleven".
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