Base | Representation |
---|---|
bin | 100110101001001100000… |
… | …0110001011100111100101 |
3 | 200210201221212121120100012 |
4 | 1031102120012023213211 |
5 | 1144004144110211031 |
6 | 15143522224500005 |
7 | 1055500533321602 |
oct | 115223006134745 |
9 | 20721855546305 |
10 | 5311131335141 |
11 | 17684901a5695 |
12 | 7193bb17a605 |
13 | 2c6ab70b28c8 |
14 | 1450badc56a9 |
15 | 9324c263b2b |
hex | 4d49818b9e5 |
5311131335141 has 4 divisors (see below), whose sum is σ = 5311696538892. Its totient is φ = 5310566131392.
The previous prime is 5311131335051. The next prime is 5311131335201. The reversal of 5311131335141 is 1415331311135.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 275550455041 + 5035580880100 = 524929^2 + 2244010^2 .
It is a cyclic number.
It is not a de Polignac number, because 5311131335141 - 226 = 5311064226277 is a prime.
It is a super-2 number, since 2×53111313351412 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5311131335098 and 5311131335107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5311131334141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282587780 + ... + 282606573.
It is an arithmetic number, because the mean of its divisors is an integer number (1327924134723).
Almost surely, 25311131335141 is an apocalyptic number.
It is an amenable number.
5311131335141 is a deficient number, since it is larger than the sum of its proper divisors (565203751).
5311131335141 is an equidigital number, since it uses as much as digits as its factorization.
5311131335141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 565203750.
The product of its digits is 8100, while the sum is 32.
Adding to 5311131335141 its reverse (1415331311135), we get a palindrome (6726462646276).
The spelling of 5311131335141 in words is "five trillion, three hundred eleven billion, one hundred thirty-one million, three hundred thirty-five thousand, one hundred forty-one".
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