Base | Representation |
---|---|
bin | 111100011000011001011000… |
… | …0001001000111111001011111 |
3 | 2120122112102222012020011222201 |
4 | 1320300302300021013321133 |
5 | 1024103321403404130043 |
6 | 5121332304352552331 |
7 | 216605024205246406 |
oct | 17060626011077137 |
9 | 2518472865204881 |
10 | 531118611005023 |
11 | 14425a1577513a8 |
12 | 4b69a4182526a7 |
13 | 19a4836858b4c2 |
14 | 95223c690a63d |
15 | 4160931ec4c4d |
hex | 1e30cb0247e5f |
531118611005023 has 2 divisors, whose sum is σ = 531118611005024. Its totient is φ = 531118611005022.
The previous prime is 531118611005009. The next prime is 531118611005029. The reversal of 531118611005023 is 320500116811135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 531118611005023 - 29 = 531118611004511 is a prime.
It is a super-3 number, since 3×5311186110050233 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531118611005029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265559305502511 + 265559305502512.
It is an arithmetic number, because the mean of its divisors is an integer number (265559305502512).
Almost surely, 2531118611005023 is an apocalyptic number.
531118611005023 is a deficient number, since it is larger than the sum of its proper divisors (1).
531118611005023 is an equidigital number, since it uses as much as digits as its factorization.
531118611005023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 37.
Adding to 531118611005023 its reverse (320500116811135), we get a palindrome (851618727816158).
The spelling of 531118611005023 in words is "five hundred thirty-one trillion, one hundred eighteen billion, six hundred eleven million, five thousand, twenty-three".
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