Base | Representation |
---|---|
bin | 110001011101110010… |
… | …001100000000100111 |
3 | 12002002112120020120222 |
4 | 301131302030000213 |
5 | 1332233414420111 |
6 | 40222204514555 |
7 | 3560122301534 |
oct | 613562140047 |
9 | 162075506528 |
10 | 53113045031 |
11 | 20585a24942 |
12 | a36354ba5b |
13 | 50159b45c7 |
14 | 27dbd61d8b |
15 | 15acd187db |
hex | c5dc8c027 |
53113045031 has 4 divisors (see below), whose sum is σ = 53531258112. Its totient is φ = 52694831952.
The previous prime is 53113044997. The next prime is 53113045049. The reversal of 53113045031 is 13054031135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53113045031 - 210 = 53113044007 is a prime.
It is a super-2 number, since 2×531130450312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53113045081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209106350 + ... + 209106603.
It is an arithmetic number, because the mean of its divisors is an integer number (13382814528).
Almost surely, 253113045031 is an apocalyptic number.
53113045031 is a deficient number, since it is larger than the sum of its proper divisors (418213081).
53113045031 is a wasteful number, since it uses less digits than its factorization.
53113045031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 418213080.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 53113045031 its reverse (13054031135), we get a palindrome (66167076166).
The spelling of 53113045031 in words is "fifty-three billion, one hundred thirteen million, forty-five thousand, thirty-one".
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