Base | Representation |
---|---|
bin | 100110101001010001111… |
… | …0000100111110001011011 |
3 | 200210202110111210212121212 |
4 | 1031102203300213301123 |
5 | 1144010044203304013 |
6 | 15143553454453335 |
7 | 1055505430453106 |
oct | 115224360476133 |
9 | 20722414725555 |
10 | 5311327009883 |
11 | 17685806a3a54 |
12 | 71945480424b |
13 | 2c6b187b428b |
14 | 1450d8d9d73d |
15 | 9325e5166a8 |
hex | 4d4a3c27c5b |
5311327009883 has 2 divisors, whose sum is σ = 5311327009884. Its totient is φ = 5311327009882.
The previous prime is 5311327009817. The next prime is 5311327010057. The reversal of 5311327009883 is 3889007231135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5311327009883 - 224 = 5311310232667 is a prime.
It is not a weakly prime, because it can be changed into another prime (5311327003883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655663504941 + 2655663504942.
It is an arithmetic number, because the mean of its divisors is an integer number (2655663504942).
Almost surely, 25311327009883 is an apocalyptic number.
5311327009883 is a deficient number, since it is larger than the sum of its proper divisors (1).
5311327009883 is an equidigital number, since it uses as much as digits as its factorization.
5311327009883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 50.
The spelling of 5311327009883 in words is "five trillion, three hundred eleven billion, three hundred twenty-seven million, nine thousand, eight hundred eighty-three".
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