Base | Representation |
---|---|
bin | 100110101001010001111… |
… | …0000100111110100001001 |
3 | 200210202110111210212212022 |
4 | 1031102203300213310021 |
5 | 1144010044203310212 |
6 | 15143553454454225 |
7 | 1055505430453445 |
oct | 115224360476411 |
9 | 20722414725768 |
10 | 5311327010057 |
11 | 17685806a40a2 |
12 | 719454804375 |
13 | 2c6b187b4393 |
14 | 1450d8d9d825 |
15 | 9325e516772 |
hex | 4d4a3c27d09 |
5311327010057 has 2 divisors, whose sum is σ = 5311327010058. Its totient is φ = 5311327010056.
The previous prime is 5311327009883. The next prime is 5311327010111. The reversal of 5311327010057 is 7500107231135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4083616473616 + 1227710536441 = 2020796^2 + 1108021^2 .
It is a cyclic number.
It is not a de Polignac number, because 5311327010057 - 218 = 5311326747913 is a prime.
It is a super-2 number, since 2×53113270100572 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5311327009999 and 5311327010026.
It is not a weakly prime, because it can be changed into another prime (5311327090057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655663505028 + 2655663505029.
It is an arithmetic number, because the mean of its divisors is an integer number (2655663505029).
Almost surely, 25311327010057 is an apocalyptic number.
It is an amenable number.
5311327010057 is a deficient number, since it is larger than the sum of its proper divisors (1).
5311327010057 is an equidigital number, since it uses as much as digits as its factorization.
5311327010057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22050, while the sum is 35.
The spelling of 5311327010057 in words is "five trillion, three hundred eleven billion, three hundred twenty-seven million, ten thousand, fifty-seven".
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