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5311433 = 22032411
BaseRepresentation
bin10100010000101111001001
3100222211220202
4110100233021
52324431213
6305501545
763101141
oct24205711
910884822
105311433
112aa8616
1219418b5
13113c77a
149c3921
156edb58
hex510bc9

5311433 has 4 divisors (see below), whose sum is σ = 5316048. Its totient is φ = 5306820.

The previous prime is 5311417. The next prime is 5311441. The reversal of 5311433 is 3341135.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 5311433 - 24 = 5311417 is a prime.

It is a super-2 number, since 2×53114332 = 56422641026978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5313433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 998 + ... + 3408.

It is an arithmetic number, because the mean of its divisors is an integer number (1329012).

Almost surely, 25311433 is an apocalyptic number.

It is an amenable number.

5311433 is a deficient number, since it is larger than the sum of its proper divisors (4615).

5311433 is a wasteful number, since it uses less digits than its factorization.

5311433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4614.

The product of its digits is 540, while the sum is 20.

The square root of 5311433 is about 2304.6546379013. The cubic root of 5311433 is about 174.4766185699.

Adding to 5311433 its reverse (3341135), we get a palindrome (8652568).

The spelling of 5311433 in words is "five million, three hundred eleven thousand, four hundred thirty-three".

Divisors: 1 2203 2411 5311433