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5311440321127 is a prime number
BaseRepresentation
bin100110101001010101010…
…0000110111101001100111
3200210202202102000200102121
41031102222200313221213
51144010312210234002
615144013023250411
71055511304545433
oct115225240675147
920722672020377
105311440321127
111768629657406
12719486749a07
132c6b36108855
1414510a0579c3
159326944a237
hex4d4aa837a67

5311440321127 has 2 divisors, whose sum is σ = 5311440321128. Its totient is φ = 5311440321126.

The previous prime is 5311440321113. The next prime is 5311440321281. The reversal of 5311440321127 is 7211230441135.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5311440321127 - 27 = 5311440320999 is a prime.

It is a super-2 number, since 2×53114403211272 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5311440321092 and 5311440321101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5311440321727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655720160563 + 2655720160564.

It is an arithmetic number, because the mean of its divisors is an integer number (2655720160564).

Almost surely, 25311440321127 is an apocalyptic number.

5311440321127 is a deficient number, since it is larger than the sum of its proper divisors (1).

5311440321127 is an equidigital number, since it uses as much as digits as its factorization.

5311440321127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 34.

The spelling of 5311440321127 in words is "five trillion, three hundred eleven billion, four hundred forty million, three hundred twenty-one thousand, one hundred twenty-seven".