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531150048133 is a prime number
BaseRepresentation
bin1111011101010110000…
…00101000101110000101
31212202222202112010001221
413232223000220232011
532200243403020013
61044001300520341
753242251626245
oct7565300505605
91782882463057
10531150048133
1119529439a731
1286b350b00b1
133b119867b13
141b9ca2b7b25
15dc3a6cc08d
hex7bab028b85

531150048133 has 2 divisors, whose sum is σ = 531150048134. Its totient is φ = 531150048132.

The previous prime is 531150048097. The next prime is 531150048181. The reversal of 531150048133 is 331840051135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 271230556804 + 259919491329 = 520798^2 + 509823^2 .

It is a cyclic number.

It is not a de Polignac number, because 531150048133 - 213 = 531150039941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531150040133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265575024066 + 265575024067.

It is an arithmetic number, because the mean of its divisors is an integer number (265575024067).

Almost surely, 2531150048133 is an apocalyptic number.

It is an amenable number.

531150048133 is a deficient number, since it is larger than the sum of its proper divisors (1).

531150048133 is an equidigital number, since it uses as much as digits as its factorization.

531150048133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 531150048133 its reverse (331840051135), we get a palindrome (862990099268).

The spelling of 531150048133 in words is "five hundred thirty-one billion, one hundred fifty million, forty-eight thousand, one hundred thirty-three".