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5311503230101 is a prime number
BaseRepresentation
bin100110101001010111001…
…0000110110010010010101
3200210202220210101210022121
41031102232100312102111
51144010424311330401
615144023151455541
71055513000346505
oct115225620662225
920722823353277
105311503230101
1117686611148a2
127194a38275b1
132c6b461638b3
14145114551a05
159326ec24ca1
hex4d4ae436495

5311503230101 has 2 divisors, whose sum is σ = 5311503230102. Its totient is φ = 5311503230100.

The previous prime is 5311503230057. The next prime is 5311503230107. The reversal of 5311503230101 is 1010323051135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5152582204900 + 158921025201 = 2269930^2 + 398649^2 .

It is a cyclic number.

It is not a de Polignac number, because 5311503230101 - 225 = 5311469675669 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5311503230107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655751615050 + 2655751615051.

It is an arithmetic number, because the mean of its divisors is an integer number (2655751615051).

Almost surely, 25311503230101 is an apocalyptic number.

It is an amenable number.

5311503230101 is a deficient number, since it is larger than the sum of its proper divisors (1).

5311503230101 is an equidigital number, since it uses as much as digits as its factorization.

5311503230101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 5311503230101 its reverse (1010323051135), we get a palindrome (6321826281236).

The spelling of 5311503230101 in words is "five trillion, three hundred eleven billion, five hundred three million, two hundred thirty thousand, one hundred one".