Base | Representation |
---|---|
bin | 10100010000111001110010 |
3 | 100222212211222 |
4 | 110100321302 |
5 | 2324441424 |
6 | 305505042 |
7 | 63103133 |
oct | 24207162 |
9 | 10885758 |
10 | 5312114 |
11 | 2aa9085 |
12 | 1942182 |
13 | 113cb82 |
14 | 9c3c8a |
15 | 6ede5e |
hex | 510e72 |
5312114 has 4 divisors (see below), whose sum is σ = 7968174. Its totient is φ = 2656056.
The previous prime is 5312107. The next prime is 5312117. The reversal of 5312114 is 4112135.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4695889 + 616225 = 2167^2 + 785^2 .
It is a junction number, because it is equal to n+sod(n) for n = 5312092 and 5312101.
It is not an unprimeable number, because it can be changed into a prime (5312117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1328027 + ... + 1328030.
Almost surely, 25312114 is an apocalyptic number.
5312114 is a deficient number, since it is larger than the sum of its proper divisors (2656060).
5312114 is a wasteful number, since it uses less digits than its factorization.
5312114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2656059.
The product of its digits is 120, while the sum is 17.
The square root of 5312114 is about 2304.8023776454. The cubic root of 5312114 is about 174.4840750321.
Adding to 5312114 its reverse (4112135), we get a palindrome (9424249).
It can be divided in two parts, 53121 and 14, that added together give a palindrome (53135).
The spelling of 5312114 in words is "five million, three hundred twelve thousand, one hundred fourteen".
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