Base | Representation |
---|---|
bin | 100110101001101101001… |
… | …0000000101001011010111 |
3 | 200210211211020001212222220 |
4 | 1031103122100011023113 |
5 | 1144013432223221310 |
6 | 15144224313353423 |
7 | 1055540201252412 |
oct | 115233220051327 |
9 | 20724736055886 |
10 | 5312241226455 |
11 | 17689aa756439 |
12 | 71966aa08873 |
13 | 2c6c33017827 |
14 | 14518457ab79 |
15 | 932b4900670 |
hex | 4d4da4052d7 |
5312241226455 has 16 divisors (see below), whose sum is σ = 8500403558400. Its totient is φ = 2832922788768.
The previous prime is 5312241226447. The next prime is 5312241226531. The reversal of 5312241226455 is 5546221422135.
It is not a de Polignac number, because 5312241226455 - 23 = 5312241226447 is a prime.
It is a super-5 number, since 5×53122412264555 (a number of 65 digits) contains 55555 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16872067 + ... + 17184036.
It is an arithmetic number, because the mean of its divisors is an integer number (531275222400).
Almost surely, 25312241226455 is an apocalyptic number.
5312241226455 is a deficient number, since it is larger than the sum of its proper divisors (3188162331945).
5312241226455 is a wasteful number, since it uses less digits than its factorization.
5312241226455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34066510.
The product of its digits is 576000, while the sum is 42.
The spelling of 5312241226455 in words is "five trillion, three hundred twelve billion, two hundred forty-one million, two hundred twenty-six thousand, four hundred fifty-five".
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