Base | Representation |
---|---|
bin | 111100011001001101111111… |
… | …1100011101010001110010100 |
3 | 2120122221020122110111110200102 |
4 | 1320302123333203222032110 |
5 | 1024112144320300323444 |
6 | 5121500233403233232 |
7 | 216616134404224460 |
oct | 17062337743521624 |
9 | 2518836573443612 |
10 | 531231612511124 |
11 | 1442a30750a0468 |
12 | 4b6b82b4218818 |
13 | 19a55c06879305 |
14 | 9527a665a94a0 |
15 | 416384785c84e |
hex | 1e326ff8ea394 |
531231612511124 has 48 divisors (see below), whose sum is σ = 1095551986773888. Its totient is φ = 220683752335488.
The previous prime is 531231612511087. The next prime is 531231612511141. The reversal of 531231612511124 is 421115216132135.
It is a super-2 number, since 2×5312316125111242 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2156339387 + ... + 2156585730.
It is an arithmetic number, because the mean of its divisors is an integer number (22823999724456).
Almost surely, 2531231612511124 is an apocalyptic number.
It is an amenable number.
531231612511124 is an abundant number, since it is smaller than the sum of its proper divisors (564320374262764).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531231612511124 is a wasteful number, since it uses less digits than its factorization.
531231612511124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4312925264 (or 4312925262 counting only the distinct ones).
The product of its digits is 43200, while the sum is 38.
Adding to 531231612511124 its reverse (421115216132135), we get a palindrome (952346828643259).
The spelling of 531231612511124 in words is "five hundred thirty-one trillion, two hundred thirty-one billion, six hundred twelve million, five hundred eleven thousand, one hundred twenty-four".
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