Base | Representation |
---|---|
bin | 111100011001001111001011… |
… | …0100000110111111001111111 |
3 | 2120122221111011222002100211220 |
4 | 1320302132112200313321333 |
5 | 1024112220012123442401 |
6 | 5121501332554244423 |
7 | 216616254226222242 |
oct | 17062362640677177 |
9 | 2518844158070756 |
10 | 531234145140351 |
11 | 1442a4154760274 |
12 | 4b6b88a0426713 |
13 | 19a5621b4913a3 |
14 | 9527c26ab1259 |
15 | 4163944d81336 |
hex | 1e32796837e7f |
531234145140351 has 8 divisors (see below), whose sum is σ = 711352160017200. Its totient is φ = 352636113511872.
The previous prime is 531234145140331. The next prime is 531234145140407. The reversal of 531234145140351 is 153041541432135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 531234145140351 - 214 = 531234145123967 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531234145140311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 379995811276 + ... + 379995812673.
It is an arithmetic number, because the mean of its divisors is an integer number (88919020002150).
Almost surely, 2531234145140351 is an apocalyptic number.
531234145140351 is a deficient number, since it is larger than the sum of its proper divisors (180118014876849).
531234145140351 is a wasteful number, since it uses less digits than its factorization.
531234145140351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 759991624185.
The product of its (nonzero) digits is 432000, while the sum is 42.
Adding to 531234145140351 its reverse (153041541432135), we get a palindrome (684275686572486).
The spelling of 531234145140351 in words is "five hundred thirty-one trillion, two hundred thirty-four billion, one hundred forty-five million, one hundred forty thousand, three hundred fifty-one".
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