Base | Representation |
---|---|
bin | 111100011001001111001111… |
… | …1111111101001110101110001 |
3 | 2120122221111121001101122100112 |
4 | 1320302132133333221311301 |
5 | 1024112220323334013040 |
6 | 5121501400435431105 |
7 | 216616261200232133 |
oct | 17062363777516561 |
9 | 2518844531348315 |
10 | 531234304204145 |
11 | 1442a4226523253 |
12 | 4b6b8925755495 |
13 | 19a56245414989 |
14 | 9527c3dc79053 |
15 | 4163953d01365 |
hex | 1e3279ffe9d71 |
531234304204145 has 4 divisors (see below), whose sum is σ = 637481165044980. Its totient is φ = 424987443363312.
The previous prime is 531234304204141. The next prime is 531234304204159. The reversal of 531234304204145 is 541402403432135.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 91933119006976 + 439301185197169 = 9588176^2 + 20959513^2 .
It is a cyclic number.
It is not a de Polignac number, because 531234304204145 - 22 = 531234304204141 is a prime.
It is not an unprimeable number, because it can be changed into a prime (531234304204141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53123430420410 + ... + 53123430420419.
It is an arithmetic number, because the mean of its divisors is an integer number (159370291261245).
Almost surely, 2531234304204145 is an apocalyptic number.
It is an amenable number.
531234304204145 is a deficient number, since it is larger than the sum of its proper divisors (106246860840835).
531234304204145 is a wasteful number, since it uses less digits than its factorization.
531234304204145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106246860840834.
The product of its (nonzero) digits is 691200, while the sum is 41.
The spelling of 531234304204145 in words is "five hundred thirty-one trillion, two hundred thirty-four billion, three hundred four million, two hundred four thousand, one hundred forty-five".
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