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531241353500353 is a prime number
BaseRepresentation
bin111100011001010010100010…
…0001010100101011011000001
32120122222011210022212222211021
41320302211010022211123001
51024112324242444002403
65121504524134345441
7216616630655245126
oct17062450412453301
92518864708788737
10531241353500353
111442a7213687891
124b6ba1724bb281
1319a56ac99ba872
14952830c18874d
154163c17b068bd
hex1e329442a56c1

531241353500353 has 2 divisors, whose sum is σ = 531241353500354. Its totient is φ = 531241353500352.

The previous prime is 531241353500323. The next prime is 531241353500413. The reversal of 531241353500353 is 353005353142135.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 275843335195024 + 255398018305329 = 16608532^2 + 15981177^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-531241353500353 is a prime.

It is a super-2 number, since 2×5312413535003532 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (531241353500323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265620676750176 + 265620676750177.

It is an arithmetic number, because the mean of its divisors is an integer number (265620676750177).

Almost surely, 2531241353500353 is an apocalyptic number.

It is an amenable number.

531241353500353 is a deficient number, since it is larger than the sum of its proper divisors (1).

531241353500353 is an equidigital number, since it uses as much as digits as its factorization.

531241353500353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1215000, while the sum is 43.

The spelling of 531241353500353 in words is "five hundred thirty-one trillion, two hundred forty-one billion, three hundred fifty-three million, five hundred thousand, three hundred fifty-three".