Base | Representation |
---|---|
bin | 111100011001010110100100… |
… | …1100100001100101000101011 |
3 | 2120200000000012021211212002111 |
4 | 1320302231021210030220223 |
5 | 1024113000032203111433 |
6 | 5121512521344343151 |
7 | 216620356041466045 |
oct | 17062551144145053 |
9 | 2520000167755074 |
10 | 531250034035243 |
11 | 1442aa96860a166 |
12 | 4b6bb995614ab7 |
13 | 19a57881216243 |
14 | 95288d2da0a95 |
15 | 4164074c2bdcd |
hex | 1e32b4990ca2b |
531250034035243 has 2 divisors, whose sum is σ = 531250034035244. Its totient is φ = 531250034035242.
The previous prime is 531250034035211. The next prime is 531250034035277. The reversal of 531250034035243 is 342530430052135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 531250034035243 - 25 = 531250034035211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531250034035196 and 531250034035205.
It is not a weakly prime, because it can be changed into another prime (531250034335243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265625017017621 + 265625017017622.
It is an arithmetic number, because the mean of its divisors is an integer number (265625017017622).
Almost surely, 2531250034035243 is an apocalyptic number.
531250034035243 is a deficient number, since it is larger than the sum of its proper divisors (1).
531250034035243 is an equidigital number, since it uses as much as digits as its factorization.
531250034035243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 531250034035243 its reverse (342530430052135), we get a palindrome (873780464087378).
The spelling of 531250034035243 in words is "five hundred thirty-one trillion, two hundred fifty billion, thirty-four million, thirty-five thousand, two hundred forty-three".
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