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531250034035243 is a prime number
BaseRepresentation
bin111100011001010110100100…
…1100100001100101000101011
32120200000000012021211212002111
41320302231021210030220223
51024113000032203111433
65121512521344343151
7216620356041466045
oct17062551144145053
92520000167755074
10531250034035243
111442aa96860a166
124b6bb995614ab7
1319a57881216243
1495288d2da0a95
154164074c2bdcd
hex1e32b4990ca2b

531250034035243 has 2 divisors, whose sum is σ = 531250034035244. Its totient is φ = 531250034035242.

The previous prime is 531250034035211. The next prime is 531250034035277. The reversal of 531250034035243 is 342530430052135.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 531250034035243 - 25 = 531250034035211 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 531250034035196 and 531250034035205.

It is not a weakly prime, because it can be changed into another prime (531250034335243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265625017017621 + 265625017017622.

It is an arithmetic number, because the mean of its divisors is an integer number (265625017017622).

Almost surely, 2531250034035243 is an apocalyptic number.

531250034035243 is a deficient number, since it is larger than the sum of its proper divisors (1).

531250034035243 is an equidigital number, since it uses as much as digits as its factorization.

531250034035243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 40.

Adding to 531250034035243 its reverse (342530430052135), we get a palindrome (873780464087378).

The spelling of 531250034035243 in words is "five hundred thirty-one trillion, two hundred fifty billion, thirty-four million, thirty-five thousand, two hundred forty-three".