Base | Representation |
---|---|
bin | 110001011110100000… |
… | …101111110001100101 |
3 | 12002010101112022212101 |
4 | 301132200233301211 |
5 | 1332300031001044 |
6 | 40223322252101 |
7 | 3560331114136 |
oct | 613640576145 |
9 | 162111468771 |
10 | 53125250149 |
11 | 20591900814 |
12 | a367657031 |
13 | 5018398a7a |
14 | 27dd81bc8d |
15 | 15ade29cd4 |
hex | c5e82fc65 |
53125250149 has 2 divisors, whose sum is σ = 53125250150. Its totient is φ = 53125250148.
The previous prime is 53125250117. The next prime is 53125250173. The reversal of 53125250149 is 94105252135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36469540900 + 16655709249 = 190970^2 + 129057^2 .
It is a cyclic number.
It is not a de Polignac number, because 53125250149 - 25 = 53125250117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53125250449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26562625074 + 26562625075.
It is an arithmetic number, because the mean of its divisors is an integer number (26562625075).
Almost surely, 253125250149 is an apocalyptic number.
It is an amenable number.
53125250149 is a deficient number, since it is larger than the sum of its proper divisors (1).
53125250149 is an equidigital number, since it uses as much as digits as its factorization.
53125250149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 53125250149 in words is "fifty-three billion, one hundred twenty-five million, two hundred fifty thousand, one hundred forty-nine".
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