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53125852181 is a prime number
BaseRepresentation
bin110001011110100011…
…000010110000010101
312002010102122220200212
4301132203002300111
51332300204232211
640223343215205
73560336202263
oct613643026025
9162112586625
1053125852181
1120592182066
12a3678a7505
135018549abc
1427dd937433
1515adee838b
hexc5e8c2c15

53125852181 has 2 divisors, whose sum is σ = 53125852182. Its totient is φ = 53125852180.

The previous prime is 53125852133. The next prime is 53125852187. The reversal of 53125852181 is 18125852135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52904140081 + 221712100 = 230009^2 + 14890^2 .

It is a cyclic number.

It is not a de Polignac number, because 53125852181 - 210 = 53125851157 is a prime.

It is a super-4 number, since 4×531258521814 (a number of 44 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53125852187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26562926090 + 26562926091.

It is an arithmetic number, because the mean of its divisors is an integer number (26562926091).

Almost surely, 253125852181 is an apocalyptic number.

It is an amenable number.

53125852181 is a deficient number, since it is larger than the sum of its proper divisors (1).

53125852181 is an equidigital number, since it uses as much as digits as its factorization.

53125852181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96000, while the sum is 41.

The spelling of 53125852181 in words is "fifty-three billion, one hundred twenty-five million, eight hundred fifty-two thousand, one hundred eighty-one".