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53130354151 = 719399476347
BaseRepresentation
bin110001011110110100…
…001101110111100111
312002010202010122020111
4301132310031313213
51332302332313101
640224023513451
73560422362460
oct613664156747
9162122118214
1053130354151
11205947774a6
12a3692b8887
135019464ca4
142800389d67
1515ae5d7251
hexc5ed0dde7

53130354151 has 8 divisors (see below), whose sum is σ = 63916215680. Its totient is φ = 43143445368.

The previous prime is 53130354127. The next prime is 53130354157. The reversal of 53130354151 is 15145303135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53130354151 - 27 = 53130354023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53130354157) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 199738041 + ... + 199738306.

It is an arithmetic number, because the mean of its divisors is an integer number (7989526960).

Almost surely, 253130354151 is an apocalyptic number.

53130354151 is a deficient number, since it is larger than the sum of its proper divisors (10785861529).

53130354151 is a wasteful number, since it uses less digits than its factorization.

53130354151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 399476373.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 53130354151 its reverse (15145303135), we get a palindrome (68275657286).

The spelling of 53130354151 in words is "fifty-three billion, one hundred thirty million, three hundred fifty-four thousand, one hundred fifty-one".

Divisors: 1 7 19 133 399476347 2796334429 7590050593 53130354151