Base | Representation |
---|---|
bin | 110001011110110100… |
… | …100011101010111101 |
3 | 12002010202022011201222 |
4 | 301132310203222331 |
5 | 1332302343142303 |
6 | 40224025443125 |
7 | 3560423214023 |
oct | 613664435275 |
9 | 162122264658 |
10 | 53130443453 |
11 | 205948285aa |
12 | a3693404a5 |
13 | 5019496829 |
14 | 28003b0713 |
15 | 15ae603938 |
hex | c5ed23abd |
53130443453 has 4 divisors (see below), whose sum is σ = 54962527740. Its totient is φ = 51298359168.
The previous prime is 53130443423. The next prime is 53130443467. The reversal of 53130443453 is 35434403135.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 14850347044 + 38280096409 = 121862^2 + 195653^2 .
It is a cyclic number.
It is not a de Polignac number, because 53130443453 - 210 = 53130442429 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53130443423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 916042100 + ... + 916042157.
It is an arithmetic number, because the mean of its divisors is an integer number (13740631935).
Almost surely, 253130443453 is an apocalyptic number.
It is an amenable number.
53130443453 is a deficient number, since it is larger than the sum of its proper divisors (1832084287).
53130443453 is a wasteful number, since it uses less digits than its factorization.
53130443453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1832084286.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 53130443453 its reverse (35434403135), we get a palindrome (88564846588).
The spelling of 53130443453 in words is "fifty-three billion, one hundred thirty million, four hundred forty-three thousand, four hundred fifty-three".
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