Base | Representation |
---|---|
bin | 110001011110110100… |
… | …110110100111001011 |
3 | 12002010202110010011101 |
4 | 301132310312213023 |
5 | 1332302403133120 |
6 | 40224031242231 |
7 | 3560423656144 |
oct | 613664664713 |
9 | 162122403141 |
10 | 53130521035 |
11 | 20594880919 |
12 | a369379377 |
13 | 50194c2c37 |
14 | 28003d0acb |
15 | 15ae61b90a |
hex | c5ed369cb |
53130521035 has 4 divisors (see below), whose sum is σ = 63756625248. Its totient is φ = 42504416824.
The previous prime is 53130521029. The next prime is 53130521051. The reversal of 53130521035 is 53012503135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53130521035 - 23 = 53130521027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53130520994 and 53130521012.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5313052099 + ... + 5313052108.
It is an arithmetic number, because the mean of its divisors is an integer number (15939156312).
Almost surely, 253130521035 is an apocalyptic number.
53130521035 is a deficient number, since it is larger than the sum of its proper divisors (10626104213).
53130521035 is a wasteful number, since it uses less digits than its factorization.
53130521035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10626104212.
The product of its (nonzero) digits is 6750, while the sum is 28.
The spelling of 53130521035 in words is "fifty-three billion, one hundred thirty million, five hundred twenty-one thousand, thirty-five".
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