Base | Representation |
---|---|
bin | 100110101010000111001… |
… | …0010101010110101001001 |
3 | 200210221002001221122110022 |
4 | 1031110032102222311021 |
5 | 1144022224231221301 |
6 | 15144451103030225 |
7 | 1055600632366262 |
oct | 115241622526511 |
9 | 20727061848408 |
10 | 5313114320201 |
11 | 1769308580716 |
12 | 71987329b375 |
13 | 2c7041b8044c |
14 | 1452284d1969 |
15 | 933163b4d1b |
hex | 4d50e4aad49 |
5313114320201 has 8 divisors (see below), whose sum is σ = 5349921215808. Its totient is φ = 5276328750000.
The previous prime is 5313114320167. The next prime is 5313114320203. The reversal of 5313114320201 is 1020234113135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5313114320201 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5313114320203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4831175 + ... + 5828076.
It is an arithmetic number, because the mean of its divisors is an integer number (668740151976).
Almost surely, 25313114320201 is an apocalyptic number.
It is an amenable number.
5313114320201 is a deficient number, since it is larger than the sum of its proper divisors (36806895607).
5313114320201 is a wasteful number, since it uses less digits than its factorization.
5313114320201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10662703.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 5313114320201 its reverse (1020234113135), we get a palindrome (6333348433336).
The spelling of 5313114320201 in words is "five trillion, three hundred thirteen billion, one hundred fourteen million, three hundred twenty thousand, two hundred one".
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