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5313114320201 = 151330110659251
BaseRepresentation
bin100110101010000111001…
…0010101010110101001001
3200210221002001221122110022
41031110032102222311021
51144022224231221301
615144451103030225
71055600632366262
oct115241622526511
920727061848408
105313114320201
111769308580716
1271987329b375
132c7041b8044c
141452284d1969
15933163b4d1b
hex4d50e4aad49

5313114320201 has 8 divisors (see below), whose sum is σ = 5349921215808. Its totient is φ = 5276328750000.

The previous prime is 5313114320167. The next prime is 5313114320203. The reversal of 5313114320201 is 1020234113135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5313114320201 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (5313114320203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4831175 + ... + 5828076.

It is an arithmetic number, because the mean of its divisors is an integer number (668740151976).

Almost surely, 25313114320201 is an apocalyptic number.

It is an amenable number.

5313114320201 is a deficient number, since it is larger than the sum of its proper divisors (36806895607).

5313114320201 is a wasteful number, since it uses less digits than its factorization.

5313114320201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10662703.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 5313114320201 its reverse (1020234113135), we get a palindrome (6333348433336).

The spelling of 5313114320201 in words is "five trillion, three hundred thirteen billion, one hundred fourteen million, three hundred twenty thousand, two hundred one".

Divisors: 1 151 3301 498451 10659251 1609546901 35186187551 5313114320201