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531314466253 is a prime number
BaseRepresentation
bin1111011101101001100…
…11110101110111001101
31212210102012220102022221
413232310303311313031
532201113000410003
61044025452535341
753246316306334
oct7566463656715
91783365812287
10531314466253
1119536918a47a
1286b80181551
133b14494454c
141ba04076d1b
15dc49d587bd
hex7bb4cf5dcd

531314466253 has 2 divisors, whose sum is σ = 531314466254. Its totient is φ = 531314466252.

The previous prime is 531314466247. The next prime is 531314466257. The reversal of 531314466253 is 352664413135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 372908078244 + 158406388009 = 610662^2 + 398003^2 .

It is a cyclic number.

It is not a de Polignac number, because 531314466253 - 29 = 531314465741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531314466257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265657233126 + 265657233127.

It is an arithmetic number, because the mean of its divisors is an integer number (265657233127).

Almost surely, 2531314466253 is an apocalyptic number.

It is an amenable number.

531314466253 is a deficient number, since it is larger than the sum of its proper divisors (1).

531314466253 is an equidigital number, since it uses as much as digits as its factorization.

531314466253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 777600, while the sum is 43.

Adding to 531314466253 its reverse (352664413135), we get a palindrome (883978879388).

The spelling of 531314466253 in words is "five hundred thirty-one billion, three hundred fourteen million, four hundred sixty-six thousand, two hundred fifty-three".