Base | Representation |
---|---|
bin | 1111011101101001101… |
… | …00001000111100011101 |
3 | 1212210102020001101112202 |
4 | 13232310310020330131 |
5 | 32201113010410123 |
6 | 1044025454341245 |
7 | 53246320053242 |
oct | 7566464107435 |
9 | 1783366041482 |
10 | 531314544413 |
11 | 195369233174 |
12 | 86b801ba825 |
13 | 3b144970cb3 |
14 | 1ba040975c9 |
15 | dc49d71a28 |
hex | 7bb4d08f1d |
531314544413 has 2 divisors, whose sum is σ = 531314544414. Its totient is φ = 531314544412.
The previous prime is 531314544377. The next prime is 531314544433. The reversal of 531314544413 is 314445413135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 457654956004 + 73659588409 = 676502^2 + 271403^2 .
It is a cyclic number.
It is not a de Polignac number, because 531314544413 - 28 = 531314544157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531314544433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265657272206 + 265657272207.
It is an arithmetic number, because the mean of its divisors is an integer number (265657272207).
Almost surely, 2531314544413 is an apocalyptic number.
It is an amenable number.
531314544413 is a deficient number, since it is larger than the sum of its proper divisors (1).
531314544413 is an equidigital number, since it uses as much as digits as its factorization.
531314544413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 172800, while the sum is 38.
Adding to 531314544413 its reverse (314445413135), we get a palindrome (845759957548).
The spelling of 531314544413 in words is "five hundred thirty-one billion, three hundred fourteen million, five hundred forty-four thousand, four hundred thirteen".
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