Base | Representation |
---|---|
bin | 1111011101101001101… |
… | …10010011100110011111 |
3 | 1212210102021010020121111 |
4 | 13232310312103212133 |
5 | 32201113132043401 |
6 | 1044025514442451 |
7 | 53246324640112 |
oct | 7566466234637 |
9 | 1783367106544 |
10 | 531315112351 |
11 | 195369590941 |
12 | 86b80433427 |
13 | 3b144b0c65a |
14 | 1ba041a4579 |
15 | dc49e34e51 |
hex | 7bb4d9399f |
531315112351 has 2 divisors, whose sum is σ = 531315112352. Its totient is φ = 531315112350.
The previous prime is 531315112303. The next prime is 531315112369. The reversal of 531315112351 is 153211513135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 531315112351 - 223 = 531306723743 is a prime.
It is a super-2 number, since 2×5313151123512 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531319112351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265657556175 + 265657556176.
It is an arithmetic number, because the mean of its divisors is an integer number (265657556176).
Almost surely, 2531315112351 is an apocalyptic number.
531315112351 is a deficient number, since it is larger than the sum of its proper divisors (1).
531315112351 is an equidigital number, since it uses as much as digits as its factorization.
531315112351 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6750, while the sum is 31.
Adding to 531315112351 its reverse (153211513135), we get a palindrome (684526625486).
The spelling of 531315112351 in words is "five hundred thirty-one billion, three hundred fifteen million, one hundred twelve thousand, three hundred fifty-one".
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