Base | Representation |
---|---|
bin | 110001011110111011… |
… | …101101110101110011 |
3 | 12002010212211112000222 |
4 | 301132323231311303 |
5 | 1332303333220430 |
6 | 40224134003255 |
7 | 3560445161240 |
oct | 613673556563 |
9 | 162125745028 |
10 | 53132320115 |
11 | 2059589a566 |
12 | a369aa652b |
13 | 50199a2a94 |
14 | 280073c5c7 |
15 | 15ae8749e5 |
hex | c5eeedd73 |
53132320115 has 32 divisors (see below), whose sum is σ = 77174985600. Its totient is φ = 34280884224.
The previous prime is 53132320067. The next prime is 53132320117. The reversal of 53132320115 is 51102323135.
It is a cyclic number.
It is not a de Polignac number, because 53132320115 - 216 = 53132254579 is a prime.
It is a super-2 number, since 2×531323201152 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53132320117) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2577389 + ... + 2597921.
It is an arithmetic number, because the mean of its divisors is an integer number (2411718300).
Almost surely, 253132320115 is an apocalyptic number.
53132320115 is a deficient number, since it is larger than the sum of its proper divisors (24042665485).
53132320115 is a wasteful number, since it uses less digits than its factorization.
53132320115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24911.
The product of its (nonzero) digits is 2700, while the sum is 26.
The spelling of 53132320115 in words is "fifty-three billion, one hundred thirty-two million, three hundred twenty thousand, one hundred fifteen".
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