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5313321114044 = 2210491266282439
BaseRepresentation
bin100110101010001101010…
…0111100001100110111100
3200210221121111001212021112
41031110122213201212330
51144023140201122134
615144523411221152
71055606023200626
oct115243247414674
920727544055245
105313321114044
111769404283a19
127199105a77b8
132c7075975b78
14145247b61c16
15933296121ce
hex4d51a9e19bc

5313321114044 has 12 divisors (see below), whose sum is σ = 9307175934000. Its totient is φ = 2654127990048.

The previous prime is 5313321113983. The next prime is 5313321114047. The reversal of 5313321114044 is 4404111233135.

It is a self number, because there is not a number n which added to its sum of digits gives 5313321114044.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5313321114047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 633137024 + ... + 633145415.

It is an arithmetic number, because the mean of its divisors is an integer number (775597994500).

Almost surely, 25313321114044 is an apocalyptic number.

It is an amenable number.

5313321114044 is a deficient number, since it is larger than the sum of its proper divisors (3993854819956).

5313321114044 is a wasteful number, since it uses less digits than its factorization.

5313321114044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1266283492 (or 1266283490 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 5313321114044 its reverse (4404111233135), we get a palindrome (9717432347179).

The spelling of 5313321114044 in words is "five trillion, three hundred thirteen billion, three hundred twenty-one million, one hundred fourteen thousand, forty-four".

Divisors: 1 2 4 1049 2098 4196 1266282439 2532564878 5065129756 1328330278511 2656660557022 5313321114044