Base | Representation |
---|---|
bin | 110001011111000100… |
… | …100100100111101001 |
3 | 12002011001012110120102 |
4 | 301133010210213221 |
5 | 1332304432013031 |
6 | 40224255435145 |
7 | 3560504000444 |
oct | 613704444751 |
9 | 162131173512 |
10 | 53134641641 |
11 | 20597135784 |
12 | a36a825ab5 |
13 | 501a306673 |
14 | 2800b8465b |
15 | 15aeb827cb |
hex | c5f1249e9 |
53134641641 has 2 divisors, whose sum is σ = 53134641642. Its totient is φ = 53134641640.
The previous prime is 53134641613. The next prime is 53134641643. The reversal of 53134641641 is 14614643135.
53134641641 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31046440000 + 22088201641 = 176200^2 + 148621^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53134641641 is a prime.
Together with 53134641643, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 53134641595 and 53134641604.
It is not a weakly prime, because it can be changed into another prime (53134641643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26567320820 + 26567320821.
It is an arithmetic number, because the mean of its divisors is an integer number (26567320821).
Almost surely, 253134641641 is an apocalyptic number.
It is an amenable number.
53134641641 is a deficient number, since it is larger than the sum of its proper divisors (1).
53134641641 is an equidigital number, since it uses as much as digits as its factorization.
53134641641 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 38.
The spelling of 53134641641 in words is "fifty-three billion, one hundred thirty-four million, six hundred forty-one thousand, six hundred forty-one".
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