531352340433 has 12 divisors (see below), whose sum is σ = 800878890240. Its totient is φ = 338833376376.

The previous prime is 531352340423. The next prime is 531352340531. The reversal of 531352340433 is 334043253135.

531352340433 is a `hidden beast` number, since 53 + 1 + 3 + 523 + 40 + 43 + 3 = 666.

It is not a de Polignac number, because 531352340433 - 2⁵ = 531352340401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (531352340423) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1283459553 + ... + 1283459966.

It is an arithmetic number, because the mean of its divisors is an integer number (66739907520).

Almost surely, 2^531352340433 is an apocalyptic number.

It is an amenable number.

531352340433 is a deficient number, since it is larger than the sum of its proper divisors (269526549807).

531352340433 is a wasteful number, since it uses less digits than its factorization.

531352340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2566919548 (or 2566919545 counting only the distinct ones).

The product of its (nonzero) digits is 194400, while the sum is 36.

Adding to 531352340433 its reverse (334043253135), we get a palindrome (865395593568).

The spelling of 531352340433 in words is "five hundred thirty-one billion, three hundred fifty-two million, three hundred forty thousand, four hundred thirty-three".