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53135244003 = 317711748001
BaseRepresentation
bin110001011111000110…
…110111101011100011
312002011002100001212010
4301133012313223203
51332310110302003
640224320404003
73560512056552
oct613706675343
9162132301763
1053135244003
11205975072a6
12a36aa76603
13501a4878aa
142800c9dd99
1515aec51003
hexc5f1b7ae3

53135244003 has 4 divisors (see below), whose sum is σ = 70846992008. Its totient is φ = 35423496000.

The previous prime is 53135243951. The next prime is 53135244053. The reversal of 53135244003 is 30044253135.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-53135244003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53135244053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8855873998 + ... + 8855874003.

It is an arithmetic number, because the mean of its divisors is an integer number (17711748002).

Almost surely, 253135244003 is an apocalyptic number.

53135244003 is a deficient number, since it is larger than the sum of its proper divisors (17711748005).

53135244003 is a wasteful number, since it uses less digits than its factorization.

53135244003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17711748004.

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 53135244003 its reverse (30044253135), we get a palindrome (83179497138).

The spelling of 53135244003 in words is "fifty-three billion, one hundred thirty-five million, two hundred forty-four thousand, three".

Divisors: 1 3 17711748001 53135244003