Base | Representation |
---|---|
bin | 110001011111011001… |
… | …000001110100100110 |
3 | 12002011102021220112021 |
4 | 301133121001310212 |
5 | 1332312320113014 |
6 | 40225010413354 |
7 | 3560600403520 |
oct | 613731016446 |
9 | 162142256467 |
10 | 53140004134 |
11 | 2059a168698 |
12 | a37059125a |
13 | 501b463439 |
14 | 280177ca10 |
15 | 15b0391624 |
hex | c5f641d26 |
53140004134 has 8 divisors (see below), whose sum is σ = 91097149968. Its totient is φ = 22774287480.
The previous prime is 53140004087. The next prime is 53140004153. The reversal of 53140004134 is 43140004135.
53140004134 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 53140004099 and 53140004108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1897857277 + ... + 1897857304.
It is an arithmetic number, because the mean of its divisors is an integer number (11387143746).
Almost surely, 253140004134 is an apocalyptic number.
53140004134 is a deficient number, since it is larger than the sum of its proper divisors (37957145834).
53140004134 is a wasteful number, since it uses less digits than its factorization.
53140004134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3795714590.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 53140004134 its reverse (43140004135), we get a palindrome (96280008269).
Subtracting from 53140004134 its reverse (43140004135), we obtain a palindrome (9999999999).
The spelling of 53140004134 in words is "fifty-three billion, one hundred forty million, four thousand, one hundred thirty-four".
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