Base | Representation |
---|---|
bin | 1111011101110011110… |
… | …11000101011101110101 |
3 | 1212210122012022202020011 |
4 | 13232321323011131311 |
5 | 32201301431020003 |
6 | 1044042155340221 |
7 | 53251410415354 |
oct | 7567173053565 |
9 | 1783565282204 |
10 | 531400251253 |
11 | 195402651a73 |
12 | 86ba4a51671 |
13 | 3b15964bac1 |
14 | 1ba1160799b |
15 | dc5265146d |
hex | 7bb9ec5775 |
531400251253 has 16 divisors (see below), whose sum is σ = 565028518320. Its totient is φ = 498038501376.
The previous prime is 531400251223. The next prime is 531400251271. The reversal of 531400251253 is 352152004135.
It can be written as a sum of positive squares in 8 ways, for example, as 60704089924 + 470696161329 = 246382^2 + 686073^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-531400251253 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531400251223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5254953 + ... + 5355121.
It is an arithmetic number, because the mean of its divisors is an integer number (35314282395).
Almost surely, 2531400251253 is an apocalyptic number.
It is an amenable number.
531400251253 is a deficient number, since it is larger than the sum of its proper divisors (33628267067).
531400251253 is a wasteful number, since it uses less digits than its factorization.
531400251253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101496.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 531400251253 its reverse (352152004135), we get a palindrome (883552255388).
The spelling of 531400251253 in words is "five hundred thirty-one billion, four hundred million, two hundred fifty-one thousand, two hundred fifty-three".
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