Base | Representation |
---|---|
bin | 1111011101110011111… |
… | …00000101011111001001 |
3 | 1212210122012211001221022 |
4 | 13232321330011133021 |
5 | 32201302012412411 |
6 | 1044042205122225 |
7 | 53251412560025 |
oct | 7567174053711 |
9 | 1783565731838 |
10 | 531400513481 |
11 | 195402810a92 |
12 | 86ba4b59375 |
13 | 3b159711276 |
14 | 1ba11675385 |
15 | dc526a3edb |
hex | 7bb9f057c9 |
531400513481 has 2 divisors, whose sum is σ = 531400513482. Its totient is φ = 531400513480.
The previous prime is 531400513433. The next prime is 531400513489. The reversal of 531400513481 is 184315004135.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 495496327225 + 35904186256 = 703915^2 + 189484^2 .
It is a cyclic number.
It is not a de Polignac number, because 531400513481 - 210 = 531400512457 is a prime.
It is a super-2 number, since 2×5314005134812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (531400513489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265700256740 + 265700256741.
It is an arithmetic number, because the mean of its divisors is an integer number (265700256741).
Almost surely, 2531400513481 is an apocalyptic number.
It is an amenable number.
531400513481 is a deficient number, since it is larger than the sum of its proper divisors (1).
531400513481 is an equidigital number, since it uses as much as digits as its factorization.
531400513481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 35.
The spelling of 531400513481 in words is "five hundred thirty-one billion, four hundred million, five hundred thirteen thousand, four hundred eighty-one".
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