Base | Representation |
---|---|
bin | 1111011101110011111… |
… | …00000101100111011001 |
3 | 1212210122012211002122212 |
4 | 13232321330011213121 |
5 | 32201302012422014 |
6 | 1044042205124505 |
7 | 53251412561411 |
oct | 7567174054731 |
9 | 1783565732585 |
10 | 531400514009 |
11 | 195402811422 |
12 | 86ba4b59735 |
13 | 3b159711591 |
14 | 1ba11675641 |
15 | dc526a423e |
hex | 7bb9f059d9 |
531400514009 has 2 divisors, whose sum is σ = 531400514010. Its totient is φ = 531400514008.
The previous prime is 531400513993. The next prime is 531400514011. The reversal of 531400514009 is 900415004135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 444462222400 + 86938291609 = 666680^2 + 294853^2 .
It is a cyclic number.
It is not a de Polignac number, because 531400514009 - 24 = 531400513993 is a prime.
Together with 531400514011, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (531400514069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265700257004 + 265700257005.
It is an arithmetic number, because the mean of its divisors is an integer number (265700257005).
Almost surely, 2531400514009 is an apocalyptic number.
It is an amenable number.
531400514009 is a deficient number, since it is larger than the sum of its proper divisors (1).
531400514009 is an equidigital number, since it uses as much as digits as its factorization.
531400514009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
The spelling of 531400514009 in words is "five hundred thirty-one billion, four hundred million, five hundred fourteen thousand, nine".
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