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531401442321 = 3177133814107
BaseRepresentation
bin1111011101110011111…
…11101000010000010001
31212210122021120021001210
413232321333220100101
532201302232123241
61044042241050333
753251423506021
oct7567177502021
91783567507053
10531401442321
11195403295922
1286ba53269a9
133b159977c89
141ba11837a81
15dc527d9316
hex7bb9fe8411

531401442321 has 4 divisors (see below), whose sum is σ = 708535256432. Its totient is φ = 354267628212.

The previous prime is 531401442293. The next prime is 531401442329. The reversal of 531401442321 is 123244104135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 531401442321 - 213 = 531401434129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (531401442329) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88566907051 + ... + 88566907056.

It is an arithmetic number, because the mean of its divisors is an integer number (177133814108).

Almost surely, 2531401442321 is an apocalyptic number.

It is an amenable number.

531401442321 is a deficient number, since it is larger than the sum of its proper divisors (177133814111).

531401442321 is a wasteful number, since it uses less digits than its factorization.

531401442321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177133814110.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 531401442321 its reverse (123244104135), we get a palindrome (654645546456).

The spelling of 531401442321 in words is "five hundred thirty-one billion, four hundred one million, four hundred forty-two thousand, three hundred twenty-one".

Divisors: 1 3 177133814107 531401442321