Base | Representation |
---|---|
bin | 11000001010100101100111… |
… | …01101011101100110100000 |
3 | 20222011011112101111212202112 |
4 | 30011102303231131212200 |
5 | 23431122414202104004 |
6 | 305004201233334452 |
7 | 14123156264543216 |
oct | 1405226355354640 |
9 | 228134471455675 |
10 | 53140350425504 |
11 | 15a287724a3861 |
12 | 5b62b57a07428 |
13 | 23861625b9924 |
14 | d1a0144aacb6 |
15 | 622480c44e6e |
hex | 3054b3b5d9a0 |
53140350425504 has 24 divisors (see below), whose sum is σ = 106335147935268. Its totient is φ = 26134598568960.
The previous prime is 53140350425411. The next prime is 53140350425507. The reversal of 53140350425504 is 40552405304135.
It can be written as a sum of positive squares in 2 ways, for example, as 40726707535504 + 12413642890000 = 6381748^2 + 3523300^2 .
It is not an unprimeable number, because it can be changed into a prime (53140350425507) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13611768137 + ... + 13611772040.
Almost surely, 253140350425504 is an apocalyptic number.
It is an amenable number.
53140350425504 is an abundant number, since it is smaller than the sum of its proper divisors (53194797509764).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53140350425504 is a wasteful number, since it uses less digits than its factorization.
53140350425504 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27223540248 (or 27223540240 counting only the distinct ones).
The product of its (nonzero) digits is 720000, while the sum is 41.
Adding to 53140350425504 its reverse (40552405304135), we get a palindrome (93692755729639).
The spelling of 53140350425504 in words is "fifty-three trillion, one hundred forty billion, three hundred fifty million, four hundred twenty-five thousand, five hundred four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •