Base | Representation |
---|---|
bin | 1111011101110100011… |
… | …01010111011010010111 |
3 | 1212210122112100012202021 |
4 | 13232322031113122113 |
5 | 32201304142341401 |
6 | 1044042450154011 |
7 | 53251466224450 |
oct | 7567215273227 |
9 | 1783575305667 |
10 | 531405043351 |
11 | 195405325386 |
12 | 86ba6582907 |
13 | 3b15a639070 |
14 | 1ba120d4127 |
15 | dc52c9b2a1 |
hex | 7bba357697 |
531405043351 has 16 divisors (see below), whose sum is σ = 657425790784. Its totient is φ = 418273818624.
The previous prime is 531405043339. The next prime is 531405043357. The reversal of 531405043351 is 153340504135.
It is a cyclic number.
It is not a de Polignac number, because 531405043351 - 211 = 531405041303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531405043357) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15110976 + ... + 15146101.
It is an arithmetic number, because the mean of its divisors is an integer number (41089111924).
Almost surely, 2531405043351 is an apocalyptic number.
531405043351 is a deficient number, since it is larger than the sum of its proper divisors (126020747433).
531405043351 is a wasteful number, since it uses less digits than its factorization.
531405043351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30257290.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 531405043351 its reverse (153340504135), we get a palindrome (684745547486).
The spelling of 531405043351 in words is "five hundred thirty-one billion, four hundred five million, forty-three thousand, three hundred fifty-one".
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