Base | Representation |
---|---|
bin | 11000001010100111010011… |
… | …00011000010001000010111 |
3 | 20222011020212100010000012201 |
4 | 30011103221203002020113 |
5 | 23431131241414124312 |
6 | 305004431021025331 |
7 | 14123220543116365 |
oct | 1405235143021027 |
9 | 228136770100181 |
10 | 53141253661207 |
11 | 15a29096336148 |
12 | 5b6316a3b5247 |
13 | 238627777701a |
14 | d1a09c42a635 |
15 | 6224d51b0557 |
hex | 3054e98c2217 |
53141253661207 has 4 divisors (see below), whose sum is σ = 54143918824680. Its totient is φ = 52138588497736.
The previous prime is 53141253661193. The next prime is 53141253661213. The reversal of 53141253661207 is 70216635214135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53141253661207 - 27 = 53141253661079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53141253661277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501332581657 + ... + 501332581762.
It is an arithmetic number, because the mean of its divisors is an integer number (13535979706170).
Almost surely, 253141253661207 is an apocalyptic number.
53141253661207 is a deficient number, since it is larger than the sum of its proper divisors (1002665163473).
53141253661207 is a wasteful number, since it uses less digits than its factorization.
53141253661207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1002665163472.
The product of its (nonzero) digits is 907200, while the sum is 46.
The spelling of 53141253661207 in words is "fifty-three trillion, one hundred forty-one billion, two hundred fifty-three million, six hundred sixty-one thousand, two hundred seven".
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